Internet-Draft | 3 Party MPC | November 2024 |
Savage & Thomson | Expires 28 May 2025 | [Page] |
A three party, honest majority system provides the most efficient protocols for Multiparty Computation (MPC). This document describes a concrete instantiation of addition and multiplication protocols that provide strong guarantees of security. The multiplication protocol provides low communication and computation costs, with addition being almost free. Any single dishonest party is detected with high probability.¶
This note is to be removed before publishing as an RFC.¶
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Multiparty Computation (MPC) can perform generic computations over inputs that are never revealed to any single entity. MPC executes an agreed function, revealing only the output of that function.¶
This makes MPC well-suited to handling data that is sensitive or private. MPC in a three-party honest majority setting is broadly recognized as being extremely efficient:¶
Addition and subtraction have zero communication cost and negligible computation cost.¶
Multiplication is possible with low communication and computation complexity.¶
Strong guarantees can be made about correctness and confidentiality, relying on only information-theoretic assumptions.¶
This document describes the basic elements required to compute basic MPC circuits in this setting. This includes the basic elements of the replicated secret sharing scheme that is used: generating shares, share addition, and revealing shared values.¶
The bulk of the document describes a protocol for multiplication over a binary field. The basic multiplication protocol scales linearly and involves 1 bit of communication per party.¶
This basic multiplication protocol does not prevent an additive attack. To deal with the additive attack, a batched validation protocol is used, which adds a sub-linear overhead. This protocol comes with significant memory costs and slightly increased computational costs, but adds negligible communication overhead and latency when there are many multiplications to validate.¶
This document describes a multiplication protocol that is specialized for use with binary fields; see Section 2.2.¶
Composing binary operations into a complete MPC system has proven to be more efficient than alternatives using prime fields in a number of applications. Some of the components in this document can be applied to rings or larger prime fields, but the validation process used here has been specialized for use with binary values.¶
A three-party honest majority MPC system performs computations on secret-shared values using a replicated scheme where each party receives two out of three additive shares of input values. Strong guarantees are provided regarding the confidentiality of inputs provided that no pair of parties reveals their shares to either of the other parties.¶
The protocols described in this document depend on having three MPC parties execute them. The protocols described here are secure with abort, even when one party is not honest.¶
Concretely, this means that a single dishonest party cannot cause the value of inputs to be revealed. Also, a single dishonest party cannot alter the output of any operation without detection. The protocol is aborted if honest parties detect an error that might indicate the actions of a dishonest party. This means that a dishonest party can disrupt the protocol.¶
MPC parties require channels to each of the other parties that provide confidentiality, integrity and peer authentication. Mutually-authenticated TLS [RFC8446] provides the necessary capabilities, however, this document does not define how to arrange communication between parties; protocols that use these mechanisms need to define how communication between parties is established.¶
The multiplication protocol described depends on shared randomness for efficiency. The protocol depends on having a way for parties to pairwise agree on random values. MPC parties can execute a coin toss protocol using the communication channel, however it is considerably more efficient to use pseudorandom secret sharing [PRSS] when there are a large number of multiplications.¶
This section describes basic operations of secret sharing (Section 2.3), reveal protocol (Section 2.5), and addition (Section 2.6). Multiplication is more involved and is the subject of subsequent sections (Section 3, Section 4).¶
The basic multiplication protocol described in Section 3 operates in any commutative ring, which will be referred to as simply a "ring". A ring is a group that defines addition and multiplication operations that are both associative and commutative. A ring has an additive inverse for every element, which enables subtraction. A ring contains a "zero" element that is an additive identity plus a "one" element that is a multiplicative identity.¶
A simple realization of a ring is formed of integers modulo a chosen integer that is greater than 1.¶
The validation protocol described in this document (see Section 4) uses a modulo 2 ring. This ring is referred to throughout as a binary field as it is also a field and it contains two values: 0 and 1. Addition and multiplication in a binary field correspond to Boolean operations. Addition in a binary field is equivalent to the Boolean exclusive OR (XOR) operation. Multiplication in a binary field is equivalent to the Boolean AND operation.¶
The security properties of the validation protocol depend on the use of a prime field of sufficient size. Fields support the same operations as rings, adding multiplicative inversion of elements, which enables a division operation. A prime field can be realized from integers modulo any prime. The validation protocol integrates the projection of values in a binary field to a larger prime field, rather than requiring a separate conversion step.¶
The output of a protocol can be revealed by sending all share values to the
entity that will receive the final result. This entity can validate the
consistency of the values it receives by ensuring that the replicated values it
receives are identical. That is, the value of x₁
received from
P₁
is the same as the value of x₁
it receives from
P₃
and so forth. If the value of shares are inconsistent, the
protocol fails. After discarding these duplicated values, the revealed value is
the sum of the shares that it receives.¶
A value can be revealed by sending adjacent parties the one share value they do
not have. That is, P₁
sends x₁
to P₂
and x₂
to P₃
; P₂
sends
x₂
to P₃
and x₃
to P₁
; P₃
sends x₃
to P₁
and x₁
to
P₂
. Each party verifies that they receive the same value twice, and aborts if
they do not.¶
If the protocol is executed correctly, each party learns the revealed value, which is the sum of the two shares it holds, plus the share that was received.¶
This basic reveal protocol requires that each party send and receive two elements. More efficient protocols are possible, but these are not defined in this document.¶
Addition of two values in this setting is trivial and requires no communication
between parties. To add x
to y
, each party adds their shares. That is, to
compute z = x + y
, each party separately computes the sum of the shares they
hold:¶
z₋ = x₋ + y₋ z₊ = x₊ + y₊¶
This produces shares of the sum without requiring communication.¶
A similar process can be used for multiplication with a value that is known to all parties, negation, and subtraction.¶
The product of two shared values, x and y, is computed using the following process.¶
Since x = x₁ + x₂ + x₃
and y = y₁ +
y₂ + y₃
the product z = x · y
can be expanded as:¶
z = (x₁ + x₂ + x₃) · (y₁ + y₂ + y₃)¶
This can be illustrated with a 3 by 3 table (Table 1):¶
y₁ | y₂ | y₃ | |
---|---|---|---|
x₁
|
x₁·y₁
|
x₁·y₂
|
x₁·y₃
|
x₂
|
x₂·y₁
|
x₂·y₂
|
x₂·y₃
|
x₃
|
x₃·y₁
|
x₃·y₂
|
x₃·y₃
|
To compute the product, each party locally computes the sum of three products as follows:¶
z₋ = x₋·y₋ + x₋·y₊ + x₊·y₋¶
To visualize this, Figure 3 shows cells labeled with the party responsible for computing that partial product:¶
The result is a non-replicated sharing of the result z = z₁ + z₂ + z₃
.¶
To reach the desired state where parties each have replicated shares of z
, each
party needs to send its share, z₋
, to the party to its left.¶
Unfortunately, each party cannot simply send this value to another party, as
this would allow the recipient to reconstruct the full input values, x
and
y
, using z₋
. To prevent this, the value of z₋
is masked with a uniformly
distributed random mask that is unknown to party P₋
.¶
Using a source of shared randomness (such as [PRSS]), each pair of helpers
generates a uniformly distributed random value known only to the two of
them. Let r₋
denote the left value (known to P₋
) and r₊
be the
right value (known to P₊
).¶
Each party uses r₋
and r₊
to create a masked value of z₋
as follows:¶
z₋ = x₋·y₋ + x₋·y₊ + x₊·y₋ + r₋ - r₊¶
Each of these three mask values are added once and subtracted once, so this
masking does not alter the result. Importantly, the value of r₊
is not
known to P₋
, which ensures that z₋
cannot be used by P₋
to recover x
or y
. Thus, z₋
is safe to send to P₋
.¶
Upon receiving a value from its right — which the recipient names z₊
— each
helper is now in possession of two-of-three shares, (z₋
, z₊
), which is a
replicated secret sharing of the product of x
and y
.¶
The basic multiplication protocol in Section 3 only offers semi-honest security. It is secure up to an additive attack; see Section 4.1. Validating multiplications allows an additive attack to be detected, ensuring that a protocol is aborted before any result is produced that might compromise the confidentiality of inputs.¶
By "additive attack", we mean that instead of sending the value z₋
, a corrupted
party could instead send z₋ + a
. In the context of boolean circuits, the only
possible additive attack is to add 1.¶
The multiplication protocol described does not prevent this. Since the value
z₋
is randomly distributed, the party (P₋
) that receives this
value cannot tell if an additive attack has been applied.¶
While an additive attack does not result in information about the inputs being revealed, it corrupts the results. If a protocol depends on revealing certain values, this sort of corruption could be used to reveal information that might not otherwise be revealed.¶
For example, if the parties were computing a function that erases a value unless it has reached some minimum such as:¶
if total_count > 1000: reveal(total_count) else: reveal(0)¶
If a corrupted helper wanted to reveal a total_count that was less than 1000, it
could add 1 to the final multiplication used to compute the condition
total_count > 1000
. The result is that values below the minimum are revealed
(and values above the minimum are erased), violating the conditions on the
protocol.¶
Before any values are revealed, the parties perform a validation protocol. This protocol confirms that all of the multiplications performed were performed correctly. That is, that no additive attack was applied by any party.¶
If this validation protocol fails, the parties abort the protocol and no values are revealed. All parties destroy the shares they hold.¶
Each of the parties produces a "Zero Knowledge Proof" (ZKP) that proves to the
two other parties (P₋
and P₊
) that all of the
multiplications it performed were done correctly. The two other parties act as
"verifiers" and validate this zero knowledge proof.¶
The validation protocol is therefore executed three times, with each party acting as a prover. Each validation can occur concurrently.¶
When operating in a boolean field, if P₌
followed the protocol
correctly, this is how they would compute z₋
:¶
z₋ = x₋·y₋ ⊕ x₋·y₊ ⊕ x₊·y₋ ⊕ r₋ ⊕ r₊¶
This can be restated as:¶
x₋·y₋ ⊕ x₋·y₊ ⊕ x₊·y₋ ⊕ r₋ ⊕ r₊ ⊕ z₋ = 0¶
The left hand side of this expression will equal zero if the protocol was followed correctly, but it will equal one if there was an additive attack.¶
Validation is made more efficient by validating multiple multiplications at the same time.¶
The above statement can be transformed to yield the result (either zero or one) as a value in a large prime field Section 4.5. These values can be summed across all the multiplications in a large batch. The total sum will be the count of additive attacks applied, which will be zero if the prover correctly followed the protocol. There will not be any wrapping around so long as the number of multiplications in the batch is smaller than the prime used to define the field.¶
For this protocol, the parties will use the field of integers mod p
, where p
is a large prime.¶
The prover (P₌
) needs to prove that for each multiplication in a batch:¶
x₋·y₋ ⊕ x₋·y₊ ⊕ x₊·y₋ ⊕ r₋ ⊕ r₊ ⊕ z₋ = 0¶
The left verifier (P₋
) knows the values of y₋
, x₋
,
r₋
, and z₋
.¶
The right verifier (P₊
) knows the values of x₊
, y₊
,
r₊
.¶
This means that the prover (P₌
) does not need to send any of these
values to the verifiers. Verifiers use information they already have to validate
the proof.¶
Since the two verifiers possess all of this information distributed amongst themselves, this approach is referred to as "Distributed Zero Knowledge Proofs".¶
[FLPCP] describes a system of zero-knowledge proofs that rely on linear operations. This is expanded in [BOYLE] to apply to three-party honest-majority MPC, requiring only O(logN) communication in total. These proofs are able to validate the computation of an inner product, or expressions of the form:¶
sum(i=0..n, uᵢ · vᵢ) = t¶
This depends on the prover (P₌
) and left verifier (P₋
)
both possessing the n-vector u
, the prover (P₌
) and the right
verifier (P₊
) possessing the n-vector v
, and the verifiers
P₋
and P₊
jointly holding shares of the target value, t
(that is, P₋
holds t₋
and P₋
holds t₊
such that t₋
+ t₊ = t
).¶
However, the security of this protocol requires the vector elements u
and v
to be members of a large field. So the first step of the validation protocol is
to take a batch of multiplications, and convert them into a dot product of
vectors with elements in a large field.¶
[BINARY] describes how to apply [FLPCP] efficiently for binary fields. When binary values are directly lifted into a large field, the XOR operation can be computed with the expression:¶
f(x, y) = x ⊕ y = x + y - 2·x·y = x·(1 - 2·y) + y¶
Using this relation, the expression that must be proven can be converted into a
dot-product of two vectors, one of which is known to both P₌
and
P₋
, the other being known to both P₌
and P₊
.¶
Rearranging terms:¶
x₋·y₊ ⊕ (x₋·y₋ ⊕ z₋ ⊕ r₋) ⊕ x₊·y₋ ⊕ r₊ = 0¶
Define:¶
e₋ = x₋·y₋ ⊕ z₋ ⊕ r₋¶
Then:¶
(x₋·y₊ ⊕ e₋) ⊕ (x₊·y₋ ⊕ r₊) = 0¶
Using: x ⊕ y = x·(1 - 2·y) + y
¶
(x₋·y₊·(1 - 2e₋) + e₋) ⊕ (x₊·y₋·(1 - 2r₊) + r₊) = 0¶
Using: x ⊕ y = x + y - 2·x·y
¶
(x₋·y₊·(1 - 2e₋) + e₋) + (x₊·y₋·(1 - 2r₊) + r₊) - 2(x₋·y₊·(1 - 2e₋) + e₋)(x₊·y₋·(1 - 2r₊) + r₊) = 0¶
Distributing and rearranging terms, plus subtracting 1/2 from both sides, produces:¶
- 2x₋·y₋·(1 - 2e₋)·y₊·x₊·(1 - 2r₊) + y₋·x₊·(1 - 2r₊) - 2e₋·y₋·x₊·(1 - 2r₊) + x₋·(1 - 2e₋)·y₊ - 2x₋·(1 - 2e₋)·y₊·r₊ + e₋ - 2e₋·r₊ + r₊ - ½ = - ½¶
Factoring allows this to be written as an expression with four terms, each with a component taken from the left and a component from the right.¶
[-2x₋·y₋·(1 - 2e₋)] · [y₊·x₊·(1 - 2r₊)] + [y₋(1 - 2e₋)] · [x₊·(1 - 2r₊)] + [x₋·(1 - 2e₋)] · [y₊(1 - 2r₊)] + [-½(1 - 2e₋)] · [(1 - 2r₊)] = -½¶
Components on the left form a vector that can be named g
, and components on
the right form a vector, h
. The result is the dot product of two four
dimensional vectors:¶
g₁·h₁ + g₂·h₂ + g₃·h₃ + g₄·h₄ = -½¶
Alternatively:¶
sum(i=1..4, gᵢ·hᵢ) = -½¶
From this point, each party can compute the vectors that they are able to.¶
P₌
and P₋
both compute gᵢ
as follows:¶
g₁ = -2·x₋·y₋·(1 - 2·e₋) g₂ = y₋·(1 - 2·e₋) g₃ = x₋·(1 - 2·e₋) g₄ = -½(1 - 2·e₋)¶
And where:¶
e₋ = x₋·y₋ ⊕ z₋ ⊕ r₋¶
P₌
and P₊
both compute hᵢ
as follows:¶
h₁ = y₊·x₊·(1 - 2·r₊) h₂ = x₊·(1 - 2·r₊) h₃ = y₊·(1 - 2·r₊) h₄ = 1 − 2·r₊¶
These vectors form the basis of later stages of the proof.¶
Each multiplication therefore produces two vectors, with each vector being
length 4. To validate a batch of m
multiplications, the prover
(P₌
), forms two vectors of length 4m
.¶
The prover (P₌
), and left verifier (P₋
) both produce the
vector u
by concatenating the vectors from all multiplications:¶
u = (g₁⁽¹⁾, g₂⁽¹⁾, g₃⁽¹⁾, g₄⁽¹⁾, g₁⁽²⁾, g₂⁽²⁾, g₃⁽²⁾, g₄⁽²⁾, … g₁⁽ᵐ⁾, g₂⁽ᵐ⁾, g₃⁽ᵐ⁾, g₄⁽ᵐ⁾)¶
The prover (P₌
) and right verifier (P₊
) both compute the vector v
in the same way:¶
v = (h₁⁽¹⁾, h₂⁽¹⁾, h₃⁽¹⁾, h₄⁽¹⁾, h₁⁽²⁾, h₂⁽²⁾, h₃⁽²⁾, h₄⁽²⁾, … , h₁⁽ᵐ⁾, h₂⁽ᵐ⁾, h₃⁽ᵐ⁾, h₄⁽ᵐ⁾)¶
If no additive attacks were applied by the prover, the dot product of these two vectors should be:¶
u·v = -m/2¶
Now that we have expressed the work of the prover as a simple dot product of two vectors of large field elements, we can use a recursive approach to prove this expression with O(logN) communication.¶
The process is iterative, where at each stage there is a pair of vectors, u
and v
, and a target, t
, where the goal is to prove that u·v = t
. The
values of u
and v
start as described in Section 4.6; with t
initially
set to a value of -m/2
.¶
At each iteration:¶
Select a compression factor L
.¶
Chunk the vectors u
and v
into s
segments of length L
.¶
The polynomial G(x)
is defined as: sum(i=0..s, pᵢ(x) · qᵢ(x))
¶
For x ∊ [0..L-1)
, this polynomial G(x)
computes the inner product of a
portion of u
and v
. So the goal becomes proving that sum(i=0..L-1, G(i)) = t
.¶
In the first iteration, the target value t
is known by all parties to be
-m/2
, so left verifier (P₋
) sets their share t₋
to -m/2
and the right
verifier P₊
sets their share t₊
to zero. In subsequent iterations the
target value will not be known to both verifiers.¶
The prover will compute the value of G(0)
, G(1)
, ... , G(2L-2)
,
the minimal number of points required to uniquely define it.¶
These 2L-1
points are split into two additive secret-shares
G₋(x)
and G₊(x)
and sent to the verifiers
P₋
and P₊
, respectively. These shares form the
distributed zero-knowledge proof.¶
The verifiers each sum together the first L-1
points they were given:
P₋
computes sum₋ = sum(i=0..L-1, G₋(i))
.
P₊
computes sum₊ = sum(i=0..L-1, G₊(i))
.
As a result, sum₋ + sum₊ = sum(0..L-1, G(i))
.¶
Now the verifiers verify the proposition sum(i=0..L-1, G(i)) = t
by having
P₋
compute b₋ = t₋ - sum₋
and
P₊
compute b₊ = t₊ - sum₊
.
They send each other these values and confirm that
b₋ + b₊ = 0
. If this test fails, the entire protocol is aborted.¶
At this point, the prover could have produced values for G(0..L-1)
that
pass this test even if they had performed an additive attack. The proof needs
to be validated by confirming that G(r) = sum(i=0..s, pᵢ(r) ·
qᵢ(r))
for a randomly selected challenge point r
. As long as
the prover cannot control the choice of r
, the likelihood that a dishonest
prover can cheat without detection is inversely proportional to the field size.¶
If we define two new vectors u′ = { p₀(r), …,
pₛ₋₁(r) }
, and v′ = { q₀(r), …,
qₛ₋₁(r) }
, then we can rewrite the statement that needs to be
proven as: u′ · v′ = G(r)
. This is of the same form as the original
statement, but with the new vectors u′
and v′
having length L
times
shorter than the original vectors.¶
u′
and v′
need not be communicated, since the prover and left verifier (P₋
)
can both compute each value pᵢ(r)
using Lagrange interpolation,
just as the prover and right verifier (P₊
) can compute each value qᵢ(r)
.¶
Each of the verifiers can use the 2L-1
points they received (their share
of G(x)
) to compute a share of G(r)
using Lagrange interpolation. These
shares become their share of a new value for t
.¶
The Fiat-Shamir heuristic can be used to generate r
by hashing the
distributed zero knowledge proof. This transforms this protocol from a
multi-round interactive protocol into a constant round protocol.¶
The vectors u
and v
are replaced by u′
and v′
, the value of t
is
set to G(r)
, and the next iteration is started.¶
The recursion ends when the vectors u
and v
have length less than L
. The
verifiers validate the soundness of the final iteration of the proof in a
simpler, more direct way; see Section 4.9.6.¶
For the first iteration, the parties will use a compression factor (L
) of 32. In
all subsequent rounds they will use a compression factor of 8.¶
Note: A larger value for L
increases the compression factor, which reduces the
overall communication cost. However, because the computation of the proof
requires Lagrange interpolation (which is O(L2) computation), a
larger compression factor quickly becomes expensive. A slightly larger
compression factor on the first round is possible because there are only a small
number of possible input values, so the work can be reduced with the use of
lookup tables if necessary.¶
p(x)
and q(x)
The prover (P₌
) and the left verifier (P₋
), chunk the vector
u
into s
chunks of length L
.¶
chunk 0: <u0, u1, …, uL-1>¶
chunk 1: <uL, uL+1, …, u2L-1>¶
…¶
chunk s-1: <u(s-1)L, u(s-1)L+1, …, usL-1>¶
If the length of u
is not divisible by L
, then the final chunk will be
padded with zeros.¶
In the first iteration there will be s = ceil(4m / L)
chunks, as the original
vectors u
and v
have length 4m
. In subsequent iterations there will be
fewer chunks.¶
They will interpret each chunk as L
points lying on a polynomial,
pᵢ(x)
of degree L-1
, corresponding to the x
coordinates { 0,
1, …, L-1 }
, that is to say they will interpret them as { pᵢ(0),
pᵢ(1), …, pᵢ(L-1) }
.¶
The prover (P₌
) and left verifier (P₋
) can find the value of
pᵢ(x)
for any other value of x
using Lagrange interpolation.¶
The prover (P₌
) uses Lagrange interpolation to compute the values {
pᵢ(L), pᵢ(L+1), …, pᵢ(2L-2) }
.¶
The same process is applied for the vector v
with the right verifier, (P₊
).¶
The prover (P₌
) and the right verifier (P₊
), chunk the vector v
into s
chunks of length L
.¶
chunk 0: <v0, v1, …, vL-1>¶
chunk 1: <vL, vL+1, …, v2L-1>¶
…¶
chunk s-1: <v(s-1)L, v(s-1)L+1, …, vsL-1>¶
As before, if the length of v
is not a multiple of L
, the final chunk will
be padded with zeros.¶
Each chunk is interpreted as L
points on a polynomial. From this the values {
qᵢ(L), qᵢ(L+1), …, qᵢ(2L-2) }
are found using
using Lagrange interpolation.¶
In order to prove that u·v = t
, the prover will compute the value of 2L-1
points on the polynomial G(x)
, which is defined as:¶
G(x) = sum(i=1..s, pᵢ(x) · qᵢ(x))¶
The prover computes the values of { G(0), G(1), …, G(2L-2) }
by incrementally
aggregating the products of { pᵢ(0), pᵢ(1), …,
pᵢ(2L-21) }
and { qᵢ(L), qᵢ(L+1), …,
qᵢ(2L-2) }
, for each chunk.¶
These 2L-1
points on the polynomial G(x)
constitute the zero-knowledge proof
that u·v = t
.¶
An equivalent method of proving u·v = t
, is to show that sum(i=0..L-1, G(i))
= t
.¶
The prover (P₌
), cannot simply send this zero-knowledge proof to the
verifiers, as doing so would release private information. Instead, the prover
produces a two-part additive secret-sharing of these 2L-1
points, sending one
share to each verifier.¶
The prover (P₌
) and the right verifier (P₊
) generate one
share using their shared randomness, which means that no communication is
needed. This share is denoted G₊(x)
.¶
The prover (P₌
) computes the other share via subtraction. That is,
G₋(x) = G(x) - G₊(x)
. This value is sent to the left verifier
(P₋
). Transmitting this share G₋(x)
involves sending 2L-1
field
values.¶
To check that sum(i=0..L-1, G(i)) = t
, the left verifier (P₋
)
computes:¶
b₋ = t₋ - sum(i=0..L-1, G₋(i))¶
Similarly, the right verifier (P₊
) computes:¶
b₊ = t₊ - sum(i=0..L-1, G₊(i))¶
The two verifiers will reveal these values b₋
and b₊
to one another, so
that each can reconstruct the full sum, b = b₋ + b₊
.¶
Each confirms that b
is zero. If it is not, the parties abort and destroy
their shares.¶
Now that the verifiers have confirmed that the proof says that there was no
additive attack, they need to validate that this was indeed a legitimate
zero-knowledge proof. The prover knows the value of t
, even if each verifier
only has shares of t
after the first round. Therefore, it is trivial for a
prover to falsify G(x)
.¶
To demonstrate that the prover has provided a valid G(x)
, a random field
element, r
, is chosen from the range [L, p)
(that is, a value that is not
part of the proof). The prover then has to show that the value of G(r)
matches what the verifiers hold. The verifiers could jointly compute this value
using the values of pᵢ(x)
and qᵢ(x)
.¶
The key requirement in choosing r
is that the prover cannot influence the
choice.¶
To minimize the rounds of communication, instead of having the verifiers select this random point, we utilize the Fiat-Shamir transform to produce a constant-round proof system.¶
The prover (P₌
) hashes the zero-knowledge proof shares it has
generated onto a field element as follows:¶
commitment = SHA256( concat( SHA256([G₋(x)]), SHA256([G₊(x)]) ) ) r = (bytes2int(commitment[..16]) % (prime - L)) + L¶
This computation does not use the entire output of the hash function, just enough to ensure that the value of r has minimal bias. For SHA-256 and a prime field modulo 261-1, the bias is in the order of 2-67, which is negligible.¶
The verifiers generate the same point r
independently. Each verifier only has
access to one set of shares from G(x)
so they each compute a hash of the shares
they have. They then send that hash to each other, after which they can concatenate
the two hash values and compute the challenge point.¶
Note that one verifier does not need to receive their shares of G(x)
from the
prover, so they are able to compute their hash before even starting any
computation.¶
Consequently, though each round depends on communication, the total latency is
two rounds. In the first, the prover sends shares of G(x)
to the left
verifier. Concurrently, the right verifier sends a hash of their shares to the
left verifier. In the second round, the left verifier sends a hash of their
shares to the right verifier.¶
At the end of each round, the prover is left with the task of proving that
G(r)
is correct based on the random challenge. r
.¶
Recall the definition of G(x)
:¶
G(x) = sum(i=0..s, pᵢ(x)·qᵢ(x))¶
This is equivalent to providing that u′ · v′ = G(r)
, where:¶
u′ = <p₀(r), p₁(r), …> v′ = <q₀(r), q₁(r), …>¶
This is a problem of exactly the same form as the original problem, except that
the length of u′
and v′
is now a factor of L
shorter than the original
length of u
and v
.¶
The prover (P₌
) and left verifier (P₋
) use Lagrange interpolation
to compute the value of pᵢ(r)
for all chunks in the range 0..s
and set this as the new vector u
.¶
Similarly, the prover (P₌
) and right verifier (P₊
) use Lagrange
interpolation to compute the value of qᵢ(r)
and set this as the new
vector v
.¶
The target value t
is set to G(r)
. The two verifiers do not learn G(r)
.
Instead, each uses Lagrange interpolation to compute a share of G(r)
. That
is:¶
t₋ = lagrange_interpolate(r, [G₋(0), G₋(1), …, G₋(2L-2)]) t₊ = lagrange_interpolate(r, [G₊(0), G₊(1), …, G₊(2L-2)])¶
The proof proceeds recursively until the length of the vectors u
and v
are
strictly less than the compression factor L
.¶
Next, the prover (P₌
) and left verifier (P₋
) jointly
generate a random field value pₘ
using shared secrets. Similarly, the prover
(P₌
) and right verifier (P₊
) generate a random field value
qₘ
using shared secrets.¶
The prover (P₌
) and left verifier (P₋
) move u₀
to index
L-1
. No data will be lost as this replaces a zero value; the length of u
is
strictly less than L
. The value at index 0 is replaced with pₘ
.¶
The prover (P₌
) and right verifier (P₊
) move v₀
to index L-1
and place the value qₘ
at index 0.¶
The prover generates a zero knowledge proof from these polynomials exactly as
before, sending each verifier 2L-1
shares of G(x)
. The process of
validation then proceeds differently.¶
Firstly, when the verifiers compute their shares of b
, they ignore the random
value at index 0 of G(x)
. That is:¶
b₋ = t₋ - sum(i=1..L-1, G₋(i)) b₊ = t₊ - sum(i=1..L-1, G₊(i))¶
Verifiers confirm that b₋ + b₊
is zero by exchanging their shares of b
.¶
Finally, the left verifier (P₋
)
computes both p₀(r)
and G₋(r)
, right verifier (P₊
)
computes q₀(r)
and G₊(r)
, and then the verifiers reveal all of
these values to each other. They then both verify that:¶
G₋(r) + G₊(r) = p₀(r) · q₀(r)¶
The addition of random masks (pₘ
and qₘ
) ensure that revealing G(r)
in
this way does not reveal anything about the value of the polynomials held by the
other party. Revealing q₀(r)
, which was computed from the random values,
only confirms that the prover did not cheat.¶
This protocol requires integration into a larger protocol, which will need to:¶
set or negotiate parameters,¶
provide communication channels,¶
agree on shared secrets, and¶
arrange the multiplications that are to be validated into batches.¶
This document recommends several parameters, which are used in the security analysis. Alternative parameters can be used, provided that they meet the stated requirements.¶
For shared secrets, pseudorandom secret sharing [PRSS] is used. For PRSS parameters, HPKE [RFC9180] with DHKEM(X25519, HKDF-SHA256), HKDF-SHA256, and AES-128-GCM is RECOMMENDED, with the same KDF being used for PRSS and AES-128 as the PRP.¶
For validation, the prime field used is modulo the Mersenne prime 261-1. Any sufficiently large prime can be used, but this value provides both good performance on 64-bit hardware and useful security margins for typical batch sizes; see TODO/below for an analysis of the batch size requirements and security properties that can be obtained by using this particular prime.¶
The Fiat-Shamir transform Section 4.9.3 used in the validation proofs can use SHA-256. However, any preimage and collision-resistant hash function can be used provided that it has a enough output entropy to avoid bias in the selected field value.¶
TODO¶
TODO¶
This document has no IANA considerations.¶
This work is a direct implementation of the protocols described in [BINARY], which builds on a lot of prior academic work on MPC.¶